Lesson 11: WHEN Condition with ARGUMENT in kotlin language

WHEN Condition with ARGUMENT in kotlin language. We have a second way to use the when statement in the Kotlin language is by passing an argument immediately after the keyword when.

Topic: WHEN Condition with ARGUMENT in kotlin language.

Problem 1

Enter an integer value between 1 and 5. Show the same in words .

Project66 – Home.kt

fun main (parameter: Array <String>) {
    print ("Enter an integer value between 1 and 5:")
    val value = readLine () !!. toInt ()
    when (value) {
        1 -> print ("one")
        2 -> print ("two")
        3 -> print ("three")
        4 -> print ("four")
        5 -> print ("five")
        else -> print ("value out of range")
    }
}
Lesson 11: WHEN Condition with ARGUMENT in kotlin language - Lesson 11: WHEN Condition with ARGUMENT in kotlin language - Lesson 11: WHEN Condition with ARGUMENT in kotlin language - WHEN Condition with ARGUMENT in kotlin language
WHEN Condition with ARGUMENT in kotlin language

As we see then we have the keyword when in brackets a variable. The contents of the variable “value” are verified with each of the indicated data.
For example if we load by keyboard 3 then the first two paths are false:

         1 -> print ("one")
         2 -> print ("two")

But the third path is verified true and goes to execute the commands arranged after the operator ->

         3 -> print ("three")

Topic: WHEN Condition with ARGUMENT in kotlin language.

Problem 2

Enter a positive integer value between 1 and 10000. Print a message indicating how many digits you have.

Project67 – Principal.kt

fun main (parameter: Array <String>) {
    print ("Enter a positive integer value between 1 and 99999:")
    val value = readLine () !!. toInt ()
    when (value){
    in 1..9 -> print ("Has 1 digit")
    in 10..99 -> print ("It has 2 digits")
    in 100..999 -> print ("It has 3 digits")
    in 1000..9999 -> print ("It has 4 digits")
    in 10000..99999 -> print ("It has 5 digits")
    else -> print ("Not in the indicated range")
}
}

Also in Kotlin we can check if a variable is within a certain range using the word in and the respective range.

Problem 3

Enter 10 integer values per keyboard. Count how many of these entered values were zero and how many 1.5 or 10.

Topic: WHEN Condition with ARGUMENT in kotlin language.

Project68 – Principal.kt

fun main (parameter: Array <String>) {
    var cant1 = 0
    var cant2 = 0
    for (i in 1..10) {
        print ("Enter an integer value:")
        val value = readLine () !!. toInt ()
        when (value){
        0 -> cant1 ++
        1, 5, 10 -> cant2 ++
    }
}
println ("Number of numbers 0 entered: $cant1")
println ("Number of numbers 1,2 or 3 entered: $cant2")
}

In this problem we have in one of the paths of the when a list of values separated by commas, if any of them matches the variable “value” then “cant2” is incremented:

             1, 5, 10 -> cant2 ++

Proposed problem

  • Charge the number of children of 10 families. Count how many have 0.1.2 or more children. Print these counters.

Solution

Topic: WHEN Condition with ARGUMENT in kotlin language.

 Project69
fun main(parametro: Array<String>){
    var count1 = 0
    var count2 = 0
    for(i in 1..10) {
        print("Ingrese un valor entero:")
        val valor = readLine()!!.toInt()
        when (valor){
            0 -> count1++
            1, 5, 10 -> count2++
        }
    }
    println("Number of families with 0 children: $count1")
    println("Number of families 1,2  3 children: $count2")
}

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